PharmPK Discussion - Second order reaction

• On 1 Jun 2012 at 17:54:15, Roger Jelliffe (jelliffe.-a-.usc.edu) sent the message
  

  
  The following message was posted to: PharmPK
  
  Dear Luis and all:
  
    I did a little further checking. You are correct that a 2nd order
  reaction is just what you say. If that is what you mean by a 2nd order
  process then you are correct.
  
    I had a different meaning in mind, one using either first order or
  2nd order differential equations. That is what I thought one meant  by a PK
  process. Here, both google and a math dictionary state that a first order
  differential equation has the 1st derivative as the highest one on the eqn,
  and a 2nd order diff eqn has the 2nd derivative as the  highest derivative
  in the eqn.
  
  Best to all,
  
  Roger
  
  Roger W. Jelliffe, M.D., F.C.P.
  Professor of Medicine,
  Co-Director, Laboratory of Applied Pharmacokinetics
  www.lapk.org
  USC Keck School of Medicine
  2250 Alcazar St, Room 134-B
  Los Angeles CA 90033
  
  

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