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The following message was posted to: PharmPK
Dear Luis and all:
I did a little further checking. You are correct that a 2nd order
reaction is just what you say. If that is what you mean by a 2nd order
process then you are correct.
I had a different meaning in mind, one using either first order or
2nd order differential equations. That is what I thought one meant by a PK
process. Here, both google and a math dictionary state that a first order
differential equation has the 1st derivative as the highest one on the eqn,
and a 2nd order diff eqn has the 2nd derivative as the highest derivative
in the eqn.
Best to all,
Roger W. Jelliffe, M.D., F.C.P.
Professor of Medicine,
Co-Director, Laboratory of Applied Pharmacokinetics
USC Keck School of Medicine
2250 Alcazar St, Room 134-B
Los Angeles CA 90033
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