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Dear all,
Can anybody please help explain the following equation to calculate ER
(extraction ratio)? I saw that many paper calculating CLorgan used this
equation but none of them provided explanation to it.
ER =fu*CLint/(Qorgan + fu*CLint)
Where,
ER= Extraction Ratio
CLint= intrinsic clearance
Qorgan=organ blood flow
fu=unbound fraction of the compound
Thanks and Regards
Xinting
[See also http://www.boomer.org/c/p4/c17/c1704.html
- db]
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The following message was posted to: PharmPK
Xinting:
That equation is derived from the basic relationship
ER = (Cin-Cout)/Cin,
Where Cin and Cout are the concentrations in and out of the clearing
organ.
There are several intermediate equations in the derivation that can be
found
in many PK texts, including Pharmacokinetic and Pharmacodynamic Data
Analysis by Gabrielson and Weiner (Apotekarsocietetan 2001)
Chris
Christopher J. Kemper, Ph.D.
Pharma Navigators, LLC
DMPK/Bioanalytical Consulting
Alliance Management/Business Analysis
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The following message was posted to: PharmPK
Xinting: Do the math:
Er,organ = CLorgan / Qorgan (for the liver is Er = CLh/LBF)
Er = (Qorgan*fu*CLint/ (Qorgan + fu*CLint)) / Qorgan
Er = fu*CLint / (Qorgan + fu*CLint)
William R. Wolowich, Pharm.D., R.Ph.
College of Pharmacy
Nova Southeastern University
wwolowic.-a-.nova.edu
[For the well-stirred model, see also http://www.boomer.org/c/p4/ja/Fig1702/Fig1702.html
- db]
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Dear Zinting,
In addition to the useful link provided by David Bourne, the following
may be helpful to understand the relationship describing the extraction
ratio.
1) total hepatic blood flow (QH),
2) fraction unbound (fU) or the extent of drug binding to blood
constituents.
3) free intrinsic clearance (CLint) or the rate-limiting step in drug
uptake from blood, intracellular transport, metabolism.
Consider a drug molecule in the hepatic sinusoids: two things may
happen:
a) the molecule escapes hepatic extraction: this chance is proportional
to Q_H (and the drug concentration in the blood);
b) the molecule enters a hepatocyte and is metabolized; this chance is
proportional to fu (only free drug enters the liver) and proportional to
CLint (and the drug concentration in the blood).
So, the chance that a molecule is extracted from the blood, is the
chance of b) divided by the som of a) and b), or (after dividing both by
the blood concentration):
E_H = (fu * CLint) / (Q_H + fu * CLint).
This is a very simplistic derivation, and should not be regarded as a
formal proof, but for understand the relationship between the three
factors (Q_H, fu, CLint) and the extraction ratio it is quite useful in
my teaching experience.
best regards,
Hans Proost
Johannes H. Proost
Dept. of Pharmacokinetics, Toxicology and Targeting
University Centre for Pharmacy
Antonius Deusinglaan 1
9713 AV Groningen, The Netherlands
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